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(x+9)(x-3)=(x+1)^2
We move all terms to the left:
(x+9)(x-3)-((x+1)^2)=0
We multiply parentheses ..
(+x^2-3x+9x-27)-((x+1)^2)=0
We calculate terms in parentheses: -((x+1)^2), so:We get rid of parentheses
(x+1)^2
x^2-3x+9x-((x+1)^2)-27=0
We calculate terms in parentheses: -((x+1)^2), so:We add all the numbers together, and all the variables
(x+1)^2
x^2+6x-((x+1)^2)-27=0
We calculate terms in parentheses: -((x+1)^2), so:
(x+1)^2
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(x+1)^2
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(x+1)^2
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(x+1)^2
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(x+1)^2
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(x+1)^2
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(x+1)^2
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(x+1)^2
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(x+1)^2
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(x+1)^2
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(x+1)^2
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(x+1)^2
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(x+1)^2
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(x+1)^2
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(x+1)^2
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(x+1)^2
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(x+1)^2
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(x+1)^2
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